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It will get trickier for interstellar distances. In Newtonian mechanics v = at, so it'd acquire rather less than the usual calendar year to succeed in c at one g acceleration. But relativity won't permit that, we will only get near to c.

Tips on how to go about calculating the scale and Electricity requirements for an area-centered linear accelerator or railgun to speed up smaller probes? 5

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Our Newtonian design is alright for just about a 12 months of acceleration and after that relativity wrecks this nice parabola:

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James JenkinsJames Jenkins 27.2k2323 gold badges108108 silver badges242242 bronze badges $endgroup$ three four $begingroup$ "1g of thrust" pointed straight up will harmony gravity, and end in you floating. "1g" (as I read it), would be the acceleration a result of the Earth's gravity; if that's how you really define it, then your acceleration decreases as you can get more (and 'come to feel considerably less pull') from Earth.

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$begingroup$ If you have the energy for a relentless 1G thrust, how much time would it get to get for the planets inside our photo voltaic more info procedure? How much time with the five nearest photo voltaic devices?

Offered limitations on acceleration for human Place flight, What exactly are the least journey situations within our photo voltaic procedure for authentic driven journeys? twenty five

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HopDavidHopDavid 16k4444 silver badges8080 bronze badges $endgroup$ nine twenty $begingroup$ Your "insert a little bit more than a calendar year for each lightyear distance" is right for an outside observer, but for someone aboard the ship, the Newtonian design is suitable for all distances (as measured before beginning acceleration): Lorentz contraction will shrink the universe during vacation to present the looks of Newtonian physics. $endgroup$

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